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Mary Seymour 1898 - 1978

Mary Seymour of Belleville, Saint Clair County, Illinois was born on January 24, 1898, and died at age 80 years old in November 1978.

Mary Seymour

Belleville, Saint Clair County, Illinois 62221

January 24, 1898

November 1978

Female

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Mary Seymour Mary Seymour (1898 - 1978)

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Mary Seymour's History: 1898 - 1978

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01/24

1898

Birthday

January 24, 1898

Birthdate

Unknown

Birthplace

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11/dd

1978

Death

November 1978

Death date

Unknown
Cause of death

Unknown
Death location

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Mary Seymour lived 7 years longer than the average family member when died at the age of 80.

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Mary Seymour lived 7 years longer than the average family member when died at the age of 80.

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Did you know?

In 1898, in the year that Mary Seymour was born, magnate and philanthropist John D. Rockefeller's Standard Oil Company controlled 84% of the oil and pipelines in the United States. Rockefeller grew Standard Oil through the merger of several other small oil companies throughout the U.S., creating a monopoly.

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In 1902, at the age of only 4 years old, Mary was alive when the first Rose Bowl game was played in Pasadena, California. Called the "Tournament East–West football game" at the time, the Michigan Wolverines (East) played the Stanford Indians (West) - the Wolverines won 49 - 0. (The Stanford captain requested an end to the game with 8 minutes remaining.) The Tournament of Roses Parade began in 1890 and the football game began as a way to boost tourism in the area.

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Mary Seymour's Family Tree & Friends

Mary Seymour's Family Tree

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Mary Seymour Jan 24, 1898 - Nov 1978

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